0=779-16t^2

Solution for 0=779-16t^2 equation:

0=779-16t^2

We move all terms to the left:

0-(779-16t^2)=0

We add all the numbers together, and all the variables

-(779-16t^2)=0

We get rid of parentheses

16t^2-779=0

a = 16; b = 0; c = -779;
Δ = b2-4ac
Δ = 02-4·16·(-779)
Δ = 49856
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{49856}=\sqrt{64*779}=\sqrt{64}*\sqrt{779}=8\sqrt{779}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{779}}{2*16}=\frac{0-8\sqrt{779}}{32}
=-\frac{8\sqrt{779}}{32}
=-\frac{\sqrt{779}}{4}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{779}}{2*16}=\frac{0+8\sqrt{779}}{32}
=\frac{8\sqrt{779}}{32}
=\frac{\sqrt{779}}{4}
$